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-x^2+12x+50=77
We move all terms to the left:
-x^2+12x+50-(77)=0
We add all the numbers together, and all the variables
-1x^2+12x-27=0
a = -1; b = 12; c = -27;
Δ = b2-4ac
Δ = 122-4·(-1)·(-27)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-6}{2*-1}=\frac{-18}{-2} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+6}{2*-1}=\frac{-6}{-2} =+3 $
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